F\hSSjrg)Nc[U5n[X15n[U5nSRXE5nU=(d [U5e![a U$f=f)aIf *iterable* has only one item, return it. If it has zero items, return *default*. If it has more than one item, raise the exception given by *too_long*, which is ``ValueError`` by default. >>> only([], default='missing') 'missing' >>> only([1]) 1 >>> only([1, 2]) # doctest: +IGNORE_EXCEPTION_DETAIL Traceback (most recent call last): ... ValueError: Expected exactly one item in iterable, but got 1, 2, and perhaps more.' >>> only([1, 2], too_long=TypeError) # doctest: +IGNORE_EXCEPTION_DETAIL Traceback (most recent call last): ... TypeError Note that :func:`only` attempts to advance *iterable* twice to ensure there is only one item. See :func:`spy` or :func:`peekable` to check iterable contents less destructively. zLExpected exactly one item in iterable, but got {!r}, {!r}, and perhaps more.)iternextformat ValueError StopIteration)iterabledefaulttoo_longit first_value second_valuemsgs 5/usr/lib/python3.13/importlib/resources/_itertools.pyonlyrsf, hBr#K *Bx  &{ A )*S/)     s A AA)NN)rrrs $r